Speednet 4.2 Solution to error during view of discrepancy report.
Due to incomplete execution of scripts the said error was coming. Please take database backups and run the POSPCC16082014.exl, POSPCCBackup16082014.exl scripts using Meghdoot Scripter after . Then execute POSPCC_V42_14082014.exl script and check login. These script files will be available in the DB Scripts folder in the Speednet folder of the cleint machine in which the upgradation for Speednet 4.2 was done.
Download Solutions
Thanks to
Shri. Rabinarayan choudhury
Phulbani Division
Odisha Circle
FEDERAL EXECUTIVE MEETING AND CENTRAL WORKING COMMITTEE MEETING AT ONGOLE
A note for campaign against the retrograde move of the Govt. for anti worker amendment of labour laws
High Court Bench asks police to use e-post to inform relatives of arrest
 |
Telephone calls won’t do, says judge
The Madras High Court Bench here has disapproved of the police practice of informing relatives or friends of the arrest of an individual on the phone and making an endorsement to that effect in the arrest memo.
Disposing of a contempt of court application, Justice N. Kirubakaran said that passing on information on the phone was not desirable since it became difficult to prove whether or not the relatives or friends were informed.
The judge agreed with R. Gandhi, counsel for the applicant, that since the Centre had discontinued telegraph service since July 15 last year, the best option available to the police was to use e-post being offered by the Department of Posts. He expressed displeasure with police officers using phones to intimate the family of those arrested in criminal cases despite a ban imposed on the practice by a Division Bench in the Principal Seat of the High Court on August 29 last.
In the present case, the applicant, K.S. Anwar alias Syed Anwar, claimed that a Sub-Inspector, attached to the Central Crime Branch here, did not follow any of the 11 directions issued by the Supreme Court in D.K. Basu’s case in 1997 while arresting him on June 25.
One of the directions states that police officers should prepare a memo of arrest containing the date and time of arrest and get it attested by at least one witness, who may either be a family member of the arrested or a respectable person of the locality where the arrest is made. The other directions state that the police should notify, as soon as practicable, the next friend or relative of the arrested of the time and place of arrest and the venue of custody through telegraph, besides sensitising the arrested to his right to have someone informed.
However, in the arrest memo pertaining to the applicant, the Sub-Inspector had just mentioned a phone number and recorded that the applicant’s wife had been informed of the arrest on that number. Such a practice could not be entertained, the judge said.
SHORTCUTS OF RATIO AND PROPORTION
Prologue: A ratio is a collation of two similar quantities prevailed by dividing one quantity by the other.
For example the ratio between 3 and 6 will be 1:2 whereas a proportion is a name we give to a statement that two ratios are equal. For example a:b=c:d.
It is very essential for any candidate to learn the shortcut tricks in order to solve ratio and proportion problems if they are preparing for any type of competitive exams like psc/ssc / ibps, etc. Let us now go through some problems which can be solved easily with short cut applications provided below.
Example 1: The incomes of A and B are in the ratio 3:2 and their expenditures are in the ratio 5:3, if each saves Rs 2000, what are their expenditures?
A. Rs 3500, Rs 1400 B. Rs 5000, Rs 1200
C. Rs 2400,Rs 1300 D. None of these
A. Rs 3500, Rs 1400 B. Rs 5000, Rs 1200
C. Rs 2400,Rs 1300 D. None of these
Solution: In order to solve this sum we need to go through the options in order to derive the correct answer Here we are been asked to find their expenditures so we need to get the ratio of amounts as given in the options similar to the ratio of expenditure stated in the problem , so starting with option A we find that 3500:1400=5:2 but as stated in the problem the ratio must be 5:3, hence option A is not correct .Checking with the rest of the options we find that our correct option is D.
Example 2:A sum of Rs 53 is divided among A,B and C in such a way that A gets Rs7 more than what B gets and B gets Rs 8 more than what C gets ,find the ratio of shares?
A. 25:18:10 B. 15:20:18
C. 51:11:12 D. 24:33:11
A. 25:18:10 B. 15:20:18
C. 51:11:12 D. 24:33:11
Solution: Now lets us take a challenge to solve this sum in a short cut method rather than using long and traditional methods. The question says a total sum of Rs 53 needs to get divided among A,B and C so first by looking at the options we should first try to find out which ratio adds up to Rs 53 so starting with option A we find that 25:18:10 i.e 25+18+10 gives us 53 also option B adds up to 53 whereas option C and option D add up to 74 and 68 hence option C and D cannot be the correct answer .Now we are left with option A and B so we have to check in this way in order to derive the final answer. As stated in the problem A gets Rs 7 more than B and B gets Rs 8 more than C which shows that option A will be the correct option.
Example 3: A sum of Rs 2000 is divided into two parts such that one part is invested at 10% p.a and the second part at 15% p.a, after 2 years if Rs 460 is received as interest then ratio of investments of first and second part is?
A. 7:4 B. 4:3C. 7:3 D. 6:4
Solution: Since total money is invested is Rs 2000,let us first check with option C and option D as only they add to 10 and we can easily find the two parts. Option C has ratio 7:3 hence the two parts are 1400 and 600 .10% on Rs 1400 for an year is Rs 140 and for two years, interest is Rs 280.15% on Rs 600 for two years is Rs 180.Now 180+280=Rs 460 hence option C is the correct answer.
Example 4: The students are in the ratio 2:3:5, if 20 students are increased in each class the ratio changes to 4:5:7.Find the total number in the three classes before the increase?
A. 309 B. 100
C. 117 D. 202
A. 309 B. 100
C. 117 D. 202
Solution: Here you have to check as if which option is divisible by 10 as the ratio stated in the problem add to 10(2:3:5).So you will find that only option D is divisible by 10 where as option A.B and C are not divisible by 10 so we need to omit out these three options .Now let the proportionate of students be 20:30:50 so the ratioadd to 100.Now if 20 students are increased then it will become 40:50:70 thus the ratio we are getting as 4:5:7 which is mentioned in the above problem. Hence B is the correct answer.
Inference:
Well, so far now I hope you have understood how to solve the sums of ratio and proportion in proper time Once again I would like to tell that proper time management and constant practice are a key to success
Well, so far now I hope you have understood how to solve the sums of ratio and proportion in proper time Once again I would like to tell that proper time management and constant practice are a key to success
FOR MORE SUCH SHORTCUTS JOIN DASMESH ACADEMY , AMRITSAR PHONE NO. 9878043061
Innovative shortcuts for finding Compound Interest without calculation...
We all know the traditional formula to compute compound interest.
CI = P*(1+R/100)^N - P
This calculation gets very tedious when N>2 (more than 2 years). The method suggested below is a very simple way to get CI/Amount after 'N' years.
You need to recall the old Pascal's Triangle in following way:
Code:
Number of Years (N)
-------------------
1 1
2 1 2 1
3 1 3 3 1
4 1 4 6 4 1
. 1 .... .... ... ... 1
Example: P = 1000, R=10 %, and N=3 years. What is CI & Amount?
Step 1: 10% of 1000 = 100, Again 10% of 100 = 10 and 10% of 10 = 1
We did this three times becoz N=3.
Step 2:
Now Amount after 3 years = 1 * 1000 + 3 * 100 + 3 * 10 + 1 * 1 = Rs.1331/-
The co-efficients - 1,3,3,1 are lifted from the pascal's triangle above.
Step 3:
CI after 3 years = 3*100 + 3*10 + 3*1 = Rs.331/- (leaving out first term in step 2)
If N =2, we would have had, Amt = 1 * 1000 + 2 * 100 + 1 * 10 = Rs. 1210/-
CI = 2 * 100 + 1* 10 = Rs. 210/-
This method is extendable for any 'N' and it avoids calculations involving higher powers on 'N' altogether!
A variant to this short cut can be applied to find depreciating value of some property. (Example, A property worth 100,000 depreciates by 10% every year, find its value after 'N' years).
N.B Prefer this method if N>=3. It will always work and it will save your time like anything.
Stay tuned and you will find many short tricks like this.
FOR MORE INNOVATIVE METHODS JOIN DASMESH ACADEMY, AMRITSAR
PHONE NO. 9878043061
No comments:
Post a Comment